y=(2v+4)(8v^2-3v+1)

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Solution for y=(2v+4)(8v^2-3v+1) equation: 


Simplifying
y = (2v + 4)(8v2 + -3v + 1)

Reorder the terms:
y = (4 + 2v)(8v2 + -3v + 1)

Reorder the terms:
y = (4 + 2v)(1 + -3v + 8v2)

Multiply (4 + 2v) * (1 + -3v + 8v2)
y = (4(1 + -3v + 8v2) + 2v * (1 + -3v + 8v2))
y = ((1 * 4 + -3v * 4 + 8v2 * 4) + 2v * (1 + -3v + 8v2))
y = ((4 + -12v + 32v2) + 2v * (1 + -3v + 8v2))
y = (4 + -12v + 32v2 + (1 * 2v + -3v * 2v + 8v2 * 2v))
y = (4 + -12v + 32v2 + (2v + -6v2 + 16v3))

Reorder the terms:
y = (4 + -12v + 2v + 32v2 + -6v2 + 16v3)

Combine like terms: -12v + 2v = -10v
y = (4 + -10v + 32v2 + -6v2 + 16v3)

Combine like terms: 32v2 + -6v2 = 26v2
y = (4 + -10v + 26v2 + 16v3)

Solving
y = 4 + -10v + 26v2 + 16v3

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Simplifying
y = 4 + -10v + 26v2 + 16v3

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